由网友(べ残念ァ)分享简介：这是我的第一个堆栈消息。希望能帮到你。This is my first stack message. Hope you can help.我有几个字符串，我需要向上突破以备后用。这里有几个我的意思...... I have several strings i need to break up for use la...

这是我的第一个堆栈消息。希望能帮到你。

This is my first stack message. Hope you can help.

我有几个字符串，我需要向上突破以备后用。这里有几个我的意思......

I have several strings i need to break up for use later. Here are a couple of examples of what i mean....

fred-064528-NEEDED  
frederic-84728957-NEEDED  
sam-028-NEEDED

正如你可以看到上面的字符串长度差别很大，所以正则表达式我认为这是实现我想要的唯一途径。我需要的是字符串的第二个连字符后的休息（' - '）。

As you can see above the string lengths vary greatly so regex i believe is the only way to achieve what i want. what i need is the rest of the string after the second hyphen ('-').

我是非常弱的正则表达式所以任何帮助将是巨大的。

i am very weak at regex so any help would be great.

在此先感谢。

推荐答案

这样的事情。这将需要任何东西（除换行符）后的第二个' - '包括' - '标志

Something like this. It will take anything (except line breaks) after the second '-' including the '-' sign.

var exp = @"^w*-w*-(.*)$";

var match = Regex.Match("frederic-84728957-NEE-DED", exp);

if (match.Success)
{
    var result = match.Groups[1]; //Result is NEE-DED

    Console.WriteLine(result);
}

编辑：我回答涉及到这个另外一个问题。除非，它要求对LINQ的解决方案，我的答案是下面，我觉得pretty的清晰。

I answered another question which relates to this. Except, it asked for a LINQ solution and my answer was the following which I find pretty clear.

http://stackoverflow.com/questions/3448269/pimp-my-linq-a-learning-exercise-based-upon-another-sa-question/3448374#3448374

var result = String.Join("-", inputData.Split('-').Skip(2));

或

var result = inputData.Split('-').Skip(2).FirstOrDefault(); //If the last part is NEE-DED then only NEE is returned.

正如其他SO线程是不是这样做的最快的方法。

As mentioned in the other SO thread it is not the fastest way of doing this.