我有一个关于 R 中日期操作的问题.我已经环顾了好几天,但在网上找不到任何帮助.我有一个数据集,其中有 id 和两个日期,另一个数据集具有相同的 id 变量、日期和价格.例如:
I have a question regarding dates manipulation in R. I've looked around for days but couldn't find any help online. I have a dataset where I have id and two dates and another dataset with the same id variable, date and price. For example:
x = data.frame(id = c("A","B","C","C"),
date1 = c("29/05/2013", "23/08/2011", "25/09/2011", "18/11/2011"),
date2 = c("10/07/2013", "04/10/2011", "10/11/2011", "15/12/2011") )
> x
id date1 date2
1 A 29/05/2013 10/07/2013
2 B 23/08/2011 04/10/2011
3 C 25/09/2011 10/11/2011
4 C 18/11/2011 15/12/2011
y = data.frame(id = c("A","A","A","B","B","B","B","B","B","C","C","C"),
date = c("21/02/2013", "19/06/2013", "31/07/2013", "07/10/2011", "16/01/2012", "10/07/2012","20/09/2012", "29/11/2012", "15/08/2014", "27/09/2011", "27/01/2012", "09/03/2012"),
price = c(126,109,111,14,13.8,14.1,14, 14.4,143,102,114,116))
> y
id date price
1 A 21/02/2013 126.0
2 A 19/06/2013 109.0
3 A 31/07/2013 111.0
4 B 07/10/2011 14.0
5 B 16/01/2012 13.8
6 B 10/07/2012 14.1
7 B 20/09/2012 14.0
8 B 29/11/2012 14.4
9 B 15/08/2014 143.0
10 C 27/09/2011 102.0
11 C 27/01/2012 114.0
12 C 09/03/2012 116.0
我想要做的是在数据集 x 中查找两个日期,如果数据集 y 中有一个日期由数据集 x 中的两个日期为相同的 id 定义,则为该日期选择价格值身份证和日期.如果没有它作为失踪.所以基本上我想得到一个像这样的最终数据集:
What I would like to do is to look for the two dates in dataset x and if there is a date in dataset y inside defined by the two dates in dataset x for the same id, to pick the value of price for that id and date. If not have it as missing. So basically I want to end up with a final dataset like that:
final = data.frame(id = c("A","B","C","C"),
date1 = c("29/05/2013", "23/08/2011", "25/09/2011", "18/11/2011"),
date2 = c("10/07/2013", "04/10/2011", "10/11/2011", "15/12/2011"),
date = c("19/06/2013", "NA", "27/09/2011", "NA"),
price = c(109,"NA",102,"NA") )
> final
id date1 date2 date price
1 A 29/05/2013 10/07/2013 19/06/2013 109
2 B 23/08/2011 04/10/2011 20/09/2012 14
3 C 25/09/2011 10/11/2011 27/09/2011 102
4 C 18/11/2011 15/12/2011 NA NA
任何帮助将不胜感激.
推荐答案
这里基于data.table
包的优秀foverlaps
解决方案.
Here a solution based on the excellent foverlaps
of the data.table
package.
library(data.table)
## coerce characters to dates ( numeric)
setDT(x)[,c("date1","date2"):=list(as.Date(date1,"%d/%m/%Y"),
as.Date(date2,"%d/%m/%Y"))]
## and a dummy date since foverlaps looks for a start,end columns
setDT(y)[,c("date1"):=as.Date(date,"%d/%m/%Y")][,date:=date1]
## y must be keyed
setkey(y,id,date,date1)
foverlaps(x,y,by.x=c("id","date1","date2"))[,
list(id,i.date1,date2,date,price)]
id i.date1 date2 date price
1: A 2013-05-29 2013-07-10 2013-06-19 109
2: B 2011-08-23 2011-10-04 <NA> NA
3: C 2011-09-25 2011-11-10 2011-09-27 102
4: C 2011-11-18 2011-12-15 <NA> NA
PS:结果并不完全相同,因为您的预期输出有错误.
PS: the result is not exactly the same because you have an error in your expected output.
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