由网友(少年玩命不玩心,)分享简介：我有一个字符串A> B，我想转换成普通有条件的前pression。如何做到这一点的 Android版表示只使用JSE。I have a String "a>b" and I want to convert into a normal conditional expression.How to do this in...

我有一个字符串A> B，我想转换成普通有条件的前pression。如何做到这一点的 Android版表示只使用JSE。

I have a String "a>b" and I want to convert into a normal conditional expression. How to do this in Android means using only JSE.

String abc = "a>10";
if(abc){
 // TO SOME TASK
}

任何帮助将AP preciated。

Any help will be appreciated.

感谢你在前进！

推荐答案

我会建议使用一个返回boolean结果的帮手的方法，这样的声明会是这个样子。

I would recommend using a "helper" method that returns a boolean result, so the statement would look something like this

String abc = "a>10";

if(stringToConditional("a>b"))
{
  //TO SOME TASK
}

private boolean stringToConditional(String str)
{
  //code here
}

从那里，助手的方法可以将字符串使用正则表达式分为三部分。乐于助人，教唆密，教程，可以发现这里。从那里，a和b可以用约翰内斯堡方法进行解析。它看起来是这样的：

From there, the "helper" method can split the string into three parts using regex. A helpful, abet dense, tutorial can be found here. From there, a and b can be parsed using JSE methods. It looks something like this:

String a = "1.21";
double a1 = Double.parseDouble(a); //a1 is now equal to 1.21

从那里，下一个步骤将是比较条件字符串（>，＆下; =，==等），以公知的运算符的列表，然后检测该操作并返回结果作为方法的布尔返回。例如：

From there, the next step would be to compare the conditional string (">", "<=", "==", etc.) to a list of known operators, and then testing the operation and returning the result as the method's boolean return. For example:

String operator = ">=";
if (operator.equals(">="))
{
  return a1>=b1;
}
...

希望我是不是太不明确或没谱。我很高兴来阐述，澄清或简化。祝你好运！

Hopefully I wasn't too unclear or off the mark. I'd be happy to elaborate, clarify or simplify. Good Luck!