由网友(Survivor（幸存者）)分享简介：如何在 Symfony 2.6 的 Twig 中呈现单个字段(单个单选框/复选框输入字段)?How can I render an individual field (single radio/checkbox input field) in Twig in Symfony 2.6?假设我有一个简单的表格:Let...

如何在 Symfony 2.6 的 Twig 中呈现单个字段(单个单选框/复选框输入字段)?

How can I render an individual field (single radio/checkbox input field) in Twig in Symfony 2.6?

假设我有一个简单的表格:

Let's say I have a simple form:

class TransportType extends AbstractType
{
    public function buildForm(FormBuilderInterface $builder, array $options)
    {
            $builder->add('transport', 'choice', array(
                'choices' => array(
                    'road' => 'Car/bus',
                    'train' => 'Train',
                ),
                'expanded' => true,
                'multiple' => false
            ));
    }

在以前的 Symfony2 版本中我可以使用:

In previous Symfony2 versions I could just use:

{{ form_widget(form.transport.road) }}
{{ form_widget(form.transport.train) }}

渲染单个单选按钮，但它似乎不再起作用.我知道我可以使用:

to render individual radio buttons, but it doesn't seem to work anymore. I know I can use:

{{ form_widget(form.transport[0]) }}
{{ form_widget(form.transport[1]) }}

但它不太灵活.当然，我可以遍历集合并检查名称，但这似乎是不必要的麻烦.没有更简单的方法吗?

but it's less flexible. Of course I can iterate over the collection and check for name, but this seems like unnecessary hassle. Isn't there an easier way?

我尝试了offsetGet(它应该按名称返回一个孩子)，但它也只适用于数组索引.

I tried offsetGet (which is supposed to return a child by name), but it also works only with array index.

推荐答案

试试这个:

{% for key, transportItem in form.transport.children %}
    {{ form_widget(transportItem) }}
{% endfor %}