由网友(幽香清远)分享简介:要引发一些未来事件我试图创造一个算法,将做到以下几点:to trigger some future events I'm trying to create an algorithm which would do the following: 生成一定量的随机日期格式 YYYY-MM-DD 的生成时间格式每个日期 H...
要引发一些未来事件我试图创造一个算法,将做到以下几点:
to trigger some future events I'm trying to create an algorithm which would do the following:
生成一定量的随机日期格式 YYYY-MM-DD
的
生成时间格式每个日期 HH:MM:SS
时间应该是(24小时)之间的922小时
添加这些项目到字符串数组中。 1完整的数组项看起来像 2013年2月25日9时45分23秒
generate a certain amount of random dates in format "yyyy-mm-dd
"
generate time for each date in format "hh:mm:ss
" Time should be (24h) between 9 and 22 hours
Add those items to a String array. 1 complete array entry looks like "2013-02-25 09:45:23
"
我还没有明确的想法如何执行此。有什么建议?
I have no clear ideas how to perform this. Any suggestions?
推荐答案
精确解你所需要的。
public class RandomDateTime {
public static void main(String[] args) {
SimpleDateFormat dfDateTime = new SimpleDateFormat("yyyy-mm-dd hh:mm:ss",Locale.getDefault());
int year = RandomDateTime.randBetween(1900, 2013);// Here you can set Range of years you need
int month = RandomDateTime.randBetween(0, 11);
int hour = RandomDateTime.randBetween(9, 22); //Hours will be displayed in between 9 to 22
int min = RandomDateTime.randBetween(0, 59);
int sec = RandomDateTime.randBetween(0, 59);
GregorianCalendar gc = new GregorianCalendar(year, month, 1);
int day = RandomDateTime.randBetween(1, gc.getActualMaximum(gc.DAY_OF_MONTH));
gc.set(year, month, day, hour, min,sec);
System.out.println(dfDateTime.format(gc.getTime()));
}
public static int randBetween(int start, int end) {
return start + (int)Math.round(Math.random() * (end - start));
}
}
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