我要实现以下算法枚举跨域用户直接和嵌套组。能否请您审阅,并给你的反馈?
I am going to implement following algorithm for enumerating across domain direct and nested groups of a user. Can you please review and give your feedback?
你能不能请查看这个算法? http://mysticpaste.com/view/9591
Can you please review this algorithm? http://mysticpaste.com/view/9591
由于用户DN,该算法返回所有的全局和通用组中的用户拥有会员trsuted域(直接和嵌套)。
Given a User DN, this algorithm returns all global and universal groups (direct and nested) of trsuted domains in which user has membership.
算法的输出被保存在FoundGroups集合变量。 (请参阅算法中)
The output of algorithm is saved in FoundGroups collection variable. (Please see algo)
谢谢
Picaro
推荐答案
这看起来是可行的。这是违背如何AD是专门用来处理这个(通用组),但是,它应该解决您的问题。
This looks like it would work. It's counter to how AD is designed to handle this (universal groups), but, it should solve your problem.
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