我觉得这是一件我应该学会了现在,我敢肯定,这是小东西,我失踪,但我可以用澄清,以确保我的做法是正确的。
I feel like this is something that I should have learned by now, and I'm sure it's something small I'm missing, but I could use clarification to make sure my approach is correct.
我使用AJAX来数据发布到自
这是一个包含PHP和HTML文件。我可以写PHP的罚款,但经过一个成功的Ajax后,我怎么只返回被通过PHP处理的数据,而不是剩余的HTML?它更好,只是张贴到一个单独的脚本?
I'm using AJAX to post data to self
which is a file that contains php and html. I can write the php fine, but after a successful ajax post, how do I only return the data that is processed via php and not the remaining html? Is it better to just post to a separate script?
推荐答案
如果您有PHP处理的文件的开头POST请求,你可以做这样的事情:
If you have the PHP handling the POST request in the beginning of the file, you can just do something like this:
<?php
if (isset($_POST['somevar'])) {
/* do something */
exit(0);
}
?>
退出()
将停止页面加载在该行。
exit()
will stop the loading of the page at that line.
我来说,认为最好是使用一个单独的脚本来处理动态AJAX请求。
I, for one, think it's better to be utilizing a separate script to deal with dynamic AJAX requests.
相关推荐
最新文章