由网友(演累、就放手吧╮)分享简介：我想创建一个广播接收器作为我的主要活动的内部类。但我确定在清单xml文件的广播接收器的问题，由于Android无法找到它。I want to create a broadcast receiver as an inner class in my main activity. But I have problem...

我想创建一个广播接收器作为我的主要活动的内部类。 但我确定在清单xml文件的广播接收器的问题， 由于Android无法找到它。

I want to create a broadcast receiver as an inner class in my main activity. But I have problems defining the broadcast receiver in manifest xml file, because android can't find it.

code：

public class MyActivity extends Activity{
    ...

    public class Receiver extends BroadcastReceiver{

        @Override
        public void onReceive(Context context, Intent intent) {
            ....
        }

    }

    ...
}

清单：

<receiver android:name=".org.danizmax.myapp.MyActivity$Receiver" android:enabled="true">
            <intent-filter>
                <action android:name="org.danizmax.myapp.BROADCAST_INITIAL_DATA"></action>
            </intent-filter>
</receiver>

我试着用：

.org.danizmax.myapp.MyActivity $接收器 org.danizmax.myapp.MyActivity $接收器 .MyActivity $接收器 。接收机

我看到别人也有类似的问题，但没有找到任何答案。

I saw others also having similar problems, but did not find any answers.

那么，这可能吗？如果不是，有什么更好的方式来使用广播接收器？

So is it possible? If not, what's better way to use broadcast receivers?

谢谢！

推荐答案

是的，这是可能的。

该接收器的android：name属性应为 .path.to.class.MyClass $ MyInnerClass

The receiver android:name attribute should look like .path.to.class.MyClass$MyInnerClass