我知道这个问题已经被问了一遍又一遍,但我仍然一直没有一个能够找到一个建议,真正帮助我。该复选框被选中,只要在列表中向下滚动。是的,我使用的是布尔数组来存储值,但是这仍然没有解决问题。这是我的code。请提出一个解决方案。谢谢你。
公开查看getView(最终诠释的立场,观点convertView,ViewGroup中父){
// TODO自动生成方法存根
最后ViewHolder持有人;
最终布尔[] itemChecked =新的布尔[30];
LayoutInflater充气= context.getLayoutInflater();
如果(convertView == NULL)
{
convertView = inflater.inflate(R.layout.custom_list,NULL);
持有人=新ViewHolder();
holder.txtViewTitle =(TextView中)convertView.findViewById(R.id.title_text);
holder.txtViewDescription =(TextView中)convertView.findViewById(R.id.description_text);
holder.cb =(复选框)convertView.findViewById(R.id.cb);
convertView.setTag(保持器);
}
其他
{
支架=(ViewHolder)convertView.getTag();
}
holder.cb.setOnCheckedChangeListener(新CompoundButton.OnCheckedChangeListener(){
@覆盖
公共无效onCheckedChanged(CompoundButton buttonView,布尔器isChecked){
// TODO自动生成方法存根
itemChecked [位置] =器isChecked;
如果(itemChecked [位置])
{
holder.cb.setChecked(真正的);
}
其他
{
holder.cb.setChecked(假);
}
holder.txtViewTitle.setText(标题[位置]);
holder.txtViewDescription.setText(介绍[位置]);
holder.cb.setChecked(itemChecked [位置]);
holder.txtViewDescription.setFocusable(假);
holder.txtViewTitle.setFocusable(假);
返回convertView;
}
}
解决方案
getView()被调用只要previously看不见的列表项需要绘制。既然你重新创建 itemChecked []
每次调用此方法时,你将有新的复选框选中和不同阵列的每个结果显示的时间。 (最终在Java中不会使该领域独特的像C)
最简单的解决方法是让 itemChecked
A classmember并设置/基于一个恢复复选框的状态。
公共类MyListAdapter扩展ArrayAdapter<对象> {
私人最终布尔[] mCheckedState;
私人最终语境mContext;
公共MyListAdapter(上下文的背景下,INT资源,INT textViewResourceId,列表和LT;对象>的对象){
超(背景下,资源,textViewResourceId,对象);
mCheckedState =新的布尔[objects.size()];
mContext =背景;
}
@覆盖
公共查看getView(INT位置,查看convertView,ViewGroup中父){
//简化为一个复选框
// ViewHolder和OnCheckedChangeListener东西离开了
复选框结果=(复选框)convertView;
如果(结果== NULL){
结果=新的复选框(mContext);
}
result.setChecked(mCheckedState [位置]);
返回结果;
}
}
I know that this question has been asked over and over again but still I've not been a able to find a suggestion that really helps me. The checkbox is unchecked whenever the list is scrolled down. Yes I'm using a boolean array to store the values but this still doesn't fix the problem. Here is my code. Please suggest a solution for this. Thank you.
public View getView(final int position, View convertView, ViewGroup parent) {
// TODO Auto-generated method stub
final ViewHolder holder;
final boolean[] itemChecked=new boolean[30];
LayoutInflater inflater = context.getLayoutInflater();
if(convertView==null)
{
convertView = inflater.inflate(R.layout.custom_list, null);
holder = new ViewHolder();
holder.txtViewTitle = (TextView) convertView.findViewById(R.id.title_text);
holder.txtViewDescription = (TextView) convertView.findViewById(R.id.description_text);
holder.cb=(CheckBox) convertView.findViewById(R.id.cb);
convertView.setTag(holder);
}
else
{
holder=(ViewHolder)convertView.getTag();
}
holder.cb.setOnCheckedChangeListener(new CompoundButton.OnCheckedChangeListener() {
@Override
public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {
// TODO Auto-generated method stub
itemChecked[position] = isChecked;
if(itemChecked[position])
{
holder.cb.setChecked(true);
}
else
{
holder.cb.setChecked(false);
}
holder.txtViewTitle.setText(title[position]);
holder.txtViewDescription.setText(description[position]);
holder.cb.setChecked(itemChecked[position]);
holder.txtViewDescription.setFocusable(false);
holder.txtViewTitle.setFocusable(false);
return convertView;
}
}
解决方案
getView() is called whenever a previously invisible list item needs to be drawn. Since you recreate itemChecked[]
each time this method is called you will have the new checkbox unchecked and a different Array for each resulting View. (final in Java does not make that field unique like in C)
Simplest way to solve that is to make itemChecked
a classmember and set / restore checkbox state based on that one.
public class MyListAdapter extends ArrayAdapter<Object> {
private final boolean[] mCheckedState;
private final Context mContext;
public MyListAdapter(Context context, int resource, int textViewResourceId, List<Object> objects) {
super(context, resource, textViewResourceId, objects);
mCheckedState = new boolean[objects.size()];
mContext = context;
}
@Override
public View getView(int position, View convertView, ViewGroup parent) {
// simplified to just a Checkbox
// ViewHolder and OnCheckedChangeListener stuff left out
CheckBox result = (CheckBox)convertView;
if (result == null) {
result = new CheckBox(mContext);
}
result.setChecked(mCheckedState[position]);
return result;
}
}
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