由网友(冷雨轩)分享简介：我有9列表视图应该受到单一的活动。所有列表可能/ maynot一次显示在屏幕上（全部在同一时间是好的）I have 9 listviews which should come under single activity. All the lists may/maynot display at a time on th...

我有9列表视图应该受到单一的活动。所有列表可能/ maynot一次显示在屏幕上（全部在同一时间是好的）

I have 9 listviews which should come under single activity. All the lists may/maynot display at a time on the screen (all at a time is nice)

推荐答案

下面是同一活动中的一个体面的解决办法，以多个的ListView。首先，所有重要的设计文件（从ANDROID ：分割屏幕在2等于零件2列表视图... ，好！）。注意，列表视图嵌入在自身LinearLayouts，这是每一个权重相同。

Here is a decent solution to more than one ListView within the same Activity. First the all-important layout file (copied from ANDROID : split the screen in 2 equals parts with 2 listviews ..., good job!). Note that the ListViews are embedded in their own LinearLayouts, which are each equally weighted.

<LinearLayout android:layout_weight="1" 
                    android:layout_height="fill_parent" 
                    android:layout_width="fill_parent">

                <ListView   android:id="@+id/list1" 
                            android:layout_height="fill_parent" 
                            android:layout_width="fill_parent">

                </ListView>
    </LinearLayout>

<LinearLayout android:layout_weight="1" 
                android:layout_height="fill_parent" 
                android:layout_width="fill_parent">

            <ListView   android:id="@+id/list2" 
                        android:layout_height="fill_parent" 
                        android:layout_width="fill_parent">

            </ListView>
</LinearLayout>

// Start java Code (you can figure out the imports)
public class AnActivity extends Activity {
private ListView lv1 = null;
private ListView lv2 = null;
private String s1[] = {"a", "b", "c", "d", "e", "f"};
private String s2[] = {"r", "s", "t", "u", "v", "w", "x"};

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);

    setContentView(R.layout.main);

        // Get UI references.
        //
    lv1 = (ListView) findViewById (R.id.list1);
    lv2 = (ListView) findViewById (R.id.list2);

    lv1.setAdapter(new ArrayAdapter<String> (this, android.R.layout.simple_list_item_1, s1));
    lv2.setAdapter(new ArrayAdapter<String> (this, android.R.layout.simple_list_item_1, s2));

} // onCreate()

} // class

很抱歉，如果有任何错别字。我编辑就在这里，在窗口，而不是在eclipse。祝你好运！

Sorry if there are any typos. I'm editing right here in the window, not in eclipse. Good luck!