由网友(污味吻)分享简介：我有以下问题：假设我有模块angular.module('myModule',['$strap'] );//module depends on AngularStrapMymodule中已定义的服务如下：myModule has service defined as following : angular.mo...

我有以下问题：

假设我有模块

angular.module('myModule',['$strap'] );//module depends on AngularStrap

Mymodule中已定义的服务如下：

myModule has service defined as following :

angular.module('myModule').service('myModuleService', ['$modal', function ($modal) 
{ ....
}); //depends on $modal service from AngularStrap

现在我需要测试myModuleService，我需要模拟模式$服务在试验（茉莉为主）myModuleService加载如下

Now I need to test myModuleService and I need to mock $modal service In test ( jasmine based ) myModuleService loaded as following

var modalMock = jasmine.createSpy();
..
angular.mock.module('myModule');
...
$provide.value('$modal', modalMock);
..
angular.mock.inject(function ($injector) {
// Initialize the service under test instance
   myService = $injector.get('myModuleService');      
});

问题是，当myModuleService被加载时，也是真实的$模式的业务加载和NOT嘲弄$模态。结果现在的问题是：什么是缺少在这里，以便与mockModal加载为myService，而不是与实际$模式？在此先感谢

The problem is when myModuleService is loaded , also real $modal service is loaded and NOT mock of the $modal. The question is: what is missing here in order to load myService with mockModal and not with real $modal ? Thanks in advance

推荐答案

我失去了你的一些测试实施细节，但以下工作：

I'm missing some of your test implementation details, but the following works:

describe('mock modal', function () {
    var modalMock = jasmine.createSpyObj('modal', ['show']),
        service;

    beforeEach(function () {
        angular.mock.module('myModule');
        angular.mock.module(function ($provide) {
            $provide.value('$modal', modalMock);
        });

        angular.mock.inject(function (myModuleService) {
            // Initialize the service under test instance
            service = myModuleService;
        });
    });

    it('mocks modal', function () {
        service.foo();
        expect(modalMock.show).toHaveBeenCalled();
    });
});

您可以找到完整的小提琴这里