由网友(淡妆)分享简介:在EF codeFirst流利的API,我可以这样写:In EF CodeFirst Fluent API I can write something like this:modelBuilder.Entity().Ignore(e => e.Property1);modelBuilder.E...
在EF codeFirst流利的API,我可以这样写:
In EF CodeFirst Fluent API I can write something like this:
modelBuilder.Entity<MyEntity>()
.Ignore(e => e.Property1);
modelBuilder.Entity<MyEntity>()
.Ignore(e => e.Property2);
如何忽略所有的性质在,但一个小小的设置,像这样的:
How to ignore all properites but a tiny set, like this:
modelBuilder.Entity<MyEntity>()
.IgnoreAllBut(e => e.ID, e => e.Important);
是否有可能写出这样的扩展方法 IgnoreAllBut
?
推荐答案
这是草案,但工作原理:
This is draft, but works:
public static void IgnoreAllBut<TStructuralType>(
this StructuralTypeConfiguration<TStructuralType> configuration,
params Expression<Func<TStructuralType, object>>[] includes)
where TStructuralType : class
{
var includeMembers = ConvertExpressionsToMembers(includes);
var type = typeof(TStructuralType);
var properties = type.GetProperties();
var typeParameter = Expression.Parameter(type);
var configurationType = configuration.GetType();
var ignoreMethod = configurationType.GetMethod("Ignore");
foreach (var property in properties)
{
if (!includeMembers.Any(member => member.Name == property.Name))
{
var propertyExpression = Expression.Property(typeParameter, property);
var lambdaExpression = Expression.Lambda(propertyExpression, typeParameter);
var genericIgnoreMethod = ignoreMethod.MakeGenericMethod(property.PropertyType);
var parameters = new object[] { lambdaExpression };
genericIgnoreMethod.Invoke(configuration, parameters);
}
}
}
private static List<MemberInfo> ConvertExpressionsToMembers<TStructuralType>(
Expression<Func<TStructuralType, object>>[] expressions)
{
var members = new List<MemberInfo>();
foreach (var lambda in expressions)
{
var expression = lambda.Body;
var memberExpression = expression as MemberExpression;
if (memberExpression == null)
{
var unaryExpression = expression as UnaryExpression;
memberExpression = unaryExpression.Operand as MemberExpression;
}
members.Add(memberExpression.Member);
}
return members;
}
感谢深灰为code在链接question.
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