由网友(13．痛失吾爱)分享简介：假设我初始化的AffineTransform如下：Suppose I initialize an AffineTransform as below:的AffineTransform AF =新AffineTransform（2，3，4，5，6，7）; AffineTransform af = new Affine...

假设我初始化的AffineTransform如下：

Suppose I initialize an AffineTransform as below:

的AffineTransform AF =新AffineTransform（2，3，4，5，6，7）;

AffineTransform af = new AffineTransform(2, 3, 4, 5, 6, 7);

我将如何创建一个使用Android的SDK等效矩阵？

How would I create an equivalent Matrix using android's sdk?

推荐答案

从AffineTransform's javadoc的：

[ x']   [  m00  m01  m02  ] [ x ]   [ m00x + m01y + m02 ]
[ y'] = [  m10  m11  m12  ] [ y ] = [ m10x + m11y + m12 ]
[ 1 ]   [   0    0    1   ] [ 1 ]   [         1         ]

不知道，但也许

Not sure, but perhaps

Matrix m = new Matrix();
m.setValues(new float[]{2,3,4,5,6,7,0,0,1});

编辑： 评论者指出，顺序应该是

Commenter points out that the order should be

m.setValues(new float[]{2,4,6,3,5,7,0,0,1});