由网友(江中客)分享简介：我想以编程方式启动管理应用程序（设置 - >应用程序 - >管理应用程序 - >应用程序信息）屏幕。我不能做到这一点。任何人都可以请帮我吗？I want to start manage application(Settings->Application->manage application->Application...

我想以编程方式启动管理应用程序（设置 - >应用程序 - >管理应用程序 - >应用程序信息）屏幕。我不能做到这一点。任何人都可以请帮我吗？

I want to start manage application(Settings->Application->manage application->Application info) screen programatically. I am unable to do it. Can anyone please help me?

在此先感谢。

推荐答案

根据本链接

在的Andr​​oid 2.3，你可以在一个ACTION_APPLICATION_DETAILS_SETTINGS意图使用startActivity（），以适当的开放的，把你的应用程序的管理屏幕

In Android 2.3, you can use startActivity() on an ACTION_APPLICATION_DETAILS_SETTINGS Intent, with a proper Uri, to bring up your app's "manage" screen

或

private static final String SCHEME = "package";

private static final String APP_PKG_NAME_21 = "com.android.settings.ApplicationPkgName";

private static final String APP_PKG_NAME_22 = "pkg";

private static final String APP_DETAILS_PACKAGE_NAME = "com.android.settings";

private static final String APP_DETAILS_CLASS_NAME = "com.android.settings.InstalledAppDetails";

public static void showInstalledAppDetails(Context context, String packageName) {
    Intent intent = new Intent();
    final int apiLevel = Build.VERSION.SDK_INT;
    if (apiLevel >= 9) { // above 2.3
        intent.setAction(Settings.ACTION_APPLICATION_DETAILS_SETTINGS);
        Uri uri = Uri.fromParts(SCHEME, packageName, null);
        intent.setData(uri);
    } else { // below 2.3
        final String appPkgName = (apiLevel == 8 ? APP_PKG_NAME_22
                : APP_PKG_NAME_21);
        intent.setAction(Intent.ACTION_VIEW);
        intent.setClassName(APP_DETAILS_PACKAGE_NAME,
                APP_DETAILS_CLASS_NAME);
        intent.putExtra(appPkgName, packageName);
    }
    context.startActivity(intent);
}