我想从我的Django的基于Web的后台Android中的JSON响应。 我得到的响应是
I am trying to get a jSON response in Android from my Django based web backend. The response I am getting is
03-19 16:32:32.120: I/System.out(7442): This si the response march API <!doctype html> <!--[if IE 7]> <html class="no-js ie7 oldie" lang="en"> <![endif]--> <!--[if IE 8]> <html class="no-js ie8 oldie" lang="en"> <![endif]--> <!--[if gt IE 8]><!--> <html class="no-js" lang="en"> <!--<![endif]--> <head> <meta charset="utf-8"> <title>ECOM</title> <meta http-equiv="X-UA-Compatible" content="IE=Edge;chrome=1" > <meta name="viewport" content="width=device-width, initial-scale=1.0, maximum-scale=1.0"> <meta name="description" content=""> <meta name="author" content=""> <meta name="apple-mobile-web-app-capable" content="yes" /> <meta name="apple-mobile-web-app-status-bar-style" content="black-translucent" /> <meta property="og:image" content="https://p.xsw88.cn/allimgs/daicuo/20230906/883.png"/> <meta property="og:title" content="-- description here --"/> <meta property="og:url" content="http://www.domain.com"/> <link rel="shortcut icon" href="/static/assets/img/favicon.ico" /> <link rel="apple-touch-icon" href="/static/assets/img/apple-touch-icon.png"> <link rel="apple-touch-icon" sizes="72x72" href="/static/assets/img/apple-touch-icon-72x72.png"> <link rel="apple-touch-icon" sizes="114x114" href="/static/assets/img/apple-touch-icon-114x114.png"> <link rel="stylesheet" href="/static/assets/css/styles.css" /> <script src="/static/assets/js/libs/modernizr.custom.60077.js"></script> <link rel="stylesheet" href="/static/assets/css/popup.css" /> <script src="/static/assets/js/jquery-1.7.2.min.js"></script> <script src="/static/assets/authentication/js/popup.js"></script> </head><body><div id="backgroundPopup"></div> <div class="header" style="text-align:center; padding-top:10px;"> <img src="/static/assets/img/Ecomlogo.png"/> </div> <div class="container-fluid" roll="main" id="main"> <div class="span6"><a href="/track_me/scan_open/1/" class="forgotpass pull-right">Track Shipment</a> <div class="login"> <div class="title"> Login </div> <div class="content-login"> <form action="." method="POST"> <div style='display:none'><input type='hidden' name='csrfmiddlewaretoken' value='xpfLvzIES8w6qzpi7kCFp0crWx9aZHGD' /></div> <input type= "text" name ="username" placeholder="Username" class="user-name"/> <input type= "Password" name="password" placeholder="Password"/> <input type="submit" class="button-login"/> <a href="#" class="forgotpass pull-right" id="forgotpass">Forgot Your Password?</a> </form> </div> </div> </div> <div class="span6"> <div class="login"> <div class="title"> Ecom Express News </div> <div class="content-login"> </div> </div> </div> </div> <!-- modal --> <div class="modal hide modal-add-revlet" id="add-revlet"> <div class="modal-header"> <a class="close" data-dismiss="modal">×</a> <h3>Record</h3> </div> <div class="modal-body"> </div> </div><!--modal end--> <div id="popupContact"> <a id="popupContactClose">x</a> </div> <!-- uncomment pre-deloy --> <!--<script src="//ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>--> <script>window.jQuery || document.write('<script src="assets/js/libs/jquery-1.7.1.min.js"></script>')</script> <!-- bootstrap --> <script src="/static/assets/js/bootstrap-transition.js"></script> <script src="/static/assets/js/bootstrap-alert.js"></script> <script src="/static/assets/js/bootstrap-modal.js"></script> <script src="/static/assets/js/bootstrap-dropdown.js"></script> <script src="/static/assets/js/bootstrap-scrollspy.js"></script> <script src="/static/assets/js/bootstrap-tab.js"></script> <script src="/static/assets/js/bootstrap-tooltip.js"></script> <script src="/static/assets/js/bootstrap-popover.js"></script> <script src="/static/assets/js/bootstrap-button.
Android的请求
Android Request
private String GetPickUpDetails(String pick_up_id2) {
StringBuilder response = new StringBuilder();
String stringUrl=Constants.PICKUP_DETAILS+pick_up_id2+"/";
URL url;
try {
url = new URL(stringUrl);
HttpURLConnection httpconn = (HttpURLConnection)url.openConnection();
if (httpconn.getResponseCode() == HttpURLConnection.HTTP_OK)
{
BufferedReader input = new BufferedReader(new InputStreamReader(httpconn.getInputStream()),8192);
String strLine = null;
while ((strLine = input.readLine()) != null)
{
response.append(strLine);
}
input.close();
}
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
System.out.println("This si the response march API "+response.toString()+" for url"+stringUrl);
return response.toString();
}
Django的浏览code
Django Views code
def pickup_details(request,id):
awb_dict={}
if request.POST:
print "this is post request",id
shipment_records=[]
shippments=Shipment.objects.filter(pickup_id=id)
for obj in shippments:
awb=obj.airwaybill_number
order_number=obj.order_number
pincode=obj.pincode
dest_sc=obj.service_centre
type=obj.product_type
if(type == "ccd"):
col_val=obj.collectable_value
else:
col_val=""
status=obj.status
city=obj.destination_city
act_wt=obj.actual_weight
dest_SC="hi"
dest_SC=obj.service_centre
#dest_SC=String(dest_SC).replace('-',' ')
record={"awb":awb,"ordernumber":order_number,"pincode":pincode,"weight":act_wt,"status":status,"city":city,"type":type,"col_value":col_val,"dest_SC":city}
shipment_records.append(record)
awb_dict["count"]=len(shipment_records)
awb_dict["shipments"]=shipment_records
#else:
#pass
return HttpResponse(simplejson.dumps(awb_dict) )
我不是那么肯定,为什么我没有得到预期的JSON响应。经手工打的网址我得到JSON响应预期
I am not so sure, why I am not getting the expected jSON response. Upon manually hitting the url I am getting the JSON response as expected
修改1 我已经试过这种方式也
EDIT 1 I have tried this approach also
try{
URL url = new URL(stringUrl);
HttpURLConnection httpconn = (HttpURLConnection)url.openConnection();
if (httpconn.getResponseCode() == HttpURLConnection.HTTP_OK)
{
BufferedReader input = new BufferedReader(new InputStreamReader(httpconn.getInputStream()),8192);
String strLine = null;
while ((strLine = input.readLine()) != null)
{
response.append(strLine);
}
input.close();
}
}catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return response.toString();
}
编辑2 我得到的错误是 HTTP 403请求试着发送请求的值没有达到API调用
EDIT 2 The error I am getting is HTTP 403 Request while trying to the sent the request as the value is not reaching the API call
修改3
我得到的HTTP响应, HttpEntity实体200.The值= response.getEntity();
为code是 org.apache .http.conn.BasicMangedEntity @ 4055505d0
EDIT 3
I am getting the HTTP response as 200.The value of HttpEntity entity = response.getEntity();
for the code is org.apache.http.conn.BasicMangedEntity@4055505d0
推荐答案
该响应重定向我到自定义登录页面,我用了 @csrf_exempt
。被要求为$ C $下再登录信息来处理信息。我增加了登录参数与我的电话,得到所需的响应
The response was redirecting me to the custom login-page where I had used @csrf_exempt
. Further login details were required for code to process the info. I added the login parameter along with my call and the desired response was obtained
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