分贝机器人分贝、机器人

由网友(森眸暖光)分享简介:我已经创建了一个让getMaxAmpitude一个应用程序,然后将其转换为分贝,但我只得到了一系列30分贝的。请问Android手机只能有一个范围30分贝,或者是它在我的code的一个问题?公共类getMaxAmpitude扩展的AsyncTask<太虚,浮法,太虚> {列DB =;INT ampitude...

我已经创建了一个让getMaxAmpitude一个应用程序,然后将其转换为分贝,但我只得到了一系列30分贝的。

请问Android手机只能有一个范围30分贝,或者是它在我的code的一个问题?

 公共类getMaxAmpitude扩展的AsyncTask<太虚,浮法,太虚> {
     列DB =;
     INT ampitude;
     浮动分贝;
     @覆盖
    公共无效doInBackground(虚空...... PARAMS){
        而(REC ==真){
            尝试{
                视频下载(250);
            }赶上(InterruptedException异常E){
                e.printStackTrace();
            }
            ampitude = recorder.getMaxAmplitude();
            DB =(浮点)(20 * Math.log10(ampitude / 700.0));
            publishProgress(DB);
        }
        返回null;
    }
    公共无效onProgressUpdate(浮...进度){

        //database.addSoundData(dB);
        分贝=(进展[0]的ToString());
 

解决方案

分贝标度总是相对的东西的措施 - 在数字音频的情况下,什么是习惯上的最大值,一个样品能够保持。这要么是 1.0 浮动样本点再presentations和 32767 有符号16位采样。计算分贝值为负,提供0dB是剪辑。

如果没有什么precisely什么记录是一个实例,我会以为这是Android的 MediaRecorder 知识 - 它采用16位有符号整数。

正确的公式在这种情况下,因此将是:

DB = 20.0 * LOG10(peakAmplitude / 32767.0)

您但是上面所使用的公式,仅仅是偏见的结果,因为它是eqivelant为:

DB = 20.0 * LOG10(peakAmplitude) - 20.0 * LOG10(700)

= 20.0 * LOG10(peakAmplitude) - 〜56.9

30分贝的动态范围的数字可能并不奇怪,如果你正在录制自带的话筒和自动增益控制已启用 - 因为这将是除非你已经采取了积极的步骤来禁用它。

9012年了,扫地机器人应该是什么样子的

I have created a application that get the getMaxAmpitude and then converts it to decibels but i only get a range of 30dB.

Does an android phone only have a range of 30dB or is it a problem in my code?

public class getMaxAmpitude extends AsyncTask<Void, Float, Void>{
     String dB = "";    
     int ampitude;
     float db;
     @Override
    public Void doInBackground(Void... params) {
        while(rec == true){
            try{
                Thread.sleep(250);
            }catch(InterruptedException e){
                e.printStackTrace();
            }
            ampitude = recorder.getMaxAmplitude();
            db =(float) (20 * Math.log10(ampitude/700.0));
            publishProgress(db);
        }
        return null;
    }
    public void onProgressUpdate(Float... progress){

        //database.addSoundData(dB);
        dB = (progress[0].toString());

解决方案

The decibel scale is always a measure relative to something - and in the case of digital audio, that something is customarily the largest value that a sample is capable of holding. This is either 1.0 for floating point representations of samples and 32767 for signed 16-bit samples. Calculated dB values are negative, with 0dB being clip.

Without knowledge of what precisely what recorder is an instance of, I will assume it's Android's MediaRecorder - which uses signed 16-bit ints.

The correct equation in this case would therefore be:

db = 20.0 * log10(peakAmplitude/32767.0)

The equation you've used above however, merely biases the results as it's eqivelant to:

db = 20.0 * log10(peakAmplitude) - 20.0 * log10(700)

=20.0*log10(peakAmplitude) - ~56.9

The dynamic range figure of 30dB might not be surprising if you're recording the onboard microphone and automatic gain control is enabled - as it will be unless you've taken active steps to disable it.

阅读全文

相关推荐

最新文章