由网友(核能气质少年)分享简介：所以，我有我的整个字符串（约10,000个字符），然后搜索该字符串的一个字（或多个字）。随着正则表达式（字）.Matches（scrappedstring）。So I have got a whole string (about 10k chars) and then searching for a word(or...

所以，我有我的整个字符串（约10,000个字符），然后搜索该字符串的一个字（或多个字）。随着正则表达式（字）.Matches（scrappedstring）。

So I have got a whole string (about 10k chars) and then searching for a word(or many words) in that string. With regex(word).Matches(scrappedstring).

但如何做到这一点，提取整个句子，包含了这个词汇。我想采取一个子串的搜索词，直到第一个点/感叹号/问号/等之后。但如何在搜索词前采取句子的一部分？

But how to do so to extract the whole sentence, that contains that word. I was thinking of taking a substring after the searched word until the first dot/exclamation mark/question mark/etc. But how to take the part of the sentence before the searched word ?

或者，也许有更好的逻辑？

Or maybe there's a better logic ?

推荐答案

如果您的边界是如。，！，？和; ，搭配跨 [^;。！？] *（wordmatch）[^;。！？] * EX pression。 它会给所有的句子所需的 wordmatch 的里面。

If your boundaries are e.g. ., !, ? and ;, match all sentences across [^.!?;]*(wordmatch)[^.!?;]* expression. It will give all sentences with desired wordmatch inside.

例如：

var s = "First sentence. Second with wordmatch ? Third one; The last wordmatch, EOM!";
var r = new Regex("[^.!?;]*(wordmatch)[^.!?;]*");
var m = r.Matches(s);

var result = Enumerable.Range(0, m.Count).Select(index => m[index].Value).ToList();