我反序列化一些的嵌套JSON具有以下内容:
字符串JSON = @{
名:查理,
someID:123,
1级:{
名:查理1,
someID:456
}
};
JavaScriptSerializer串行=新JavaScriptSerializer();
字典<字符串,对象>数据= serializer.Deserialize<字典<字符串,对象>>(JSON);
在此操作后,每个字典键的值可以是另一字典,依此类推,多级深
我想这样做的是扁平化的多层次的数据的所以它只是一个平面阵列/列表,只有所有的JSON属性名称和它们的值。所以,我最终的东西是这样的:
的名字,查理
someID,123
名字,查理1
someID,456
我是标题下使用的路径的的SelectMany()的等等,但不能争吵它做什么我之后。
之类的,我一直在用这样的事情左右摇摆:
VAR OBJ = data.Values.SelectMany<对象字典<字符串,对象>>(X => X);
![Python基础13 字典中的嵌套](https://p.xsw88.cn/allimgs/daicuo/20230907/4679.png)
但我不能够满足编译器。是的,我很失落。
我使用.NET 3.5。
解决方案 Func键<字典<字符串,对象>中的IEnumerable< KeyValuePair<字符串,对象>>>扁平化= NULL;
扁平化=字典=> dict.SelectMany(KV =>
kv.Value是字典<字符串,对象>
?扁平化((词典<字符串,对象>)kv.Value)
新名单,其中,KeyValuePair<字符串,对象>>(){} KV
);
变种flatList =弄平(数据).ToList();
I am deserializing some nested JSON with the following:
string json = @"{
""name"": ""charlie"",
""someID"": 123,
""level1"" : {
""name"": ""charlie 1"",
""someID"": 456
}
}";
JavaScriptSerializer serializer = new JavaScriptSerializer();
Dictionary<string, object> data = serializer.Deserialize<Dictionary<string, object>>(json);
Once this is done, the values of each dictionary key may be another Dictionary, and so on, multiple levels deep.
What I would like to do is to flatten the multi-level data so it's just a flat Array/List, with just all the JSON attribute names and their values. So that I end up with something like this:
name, "charlie"
someID, 123
name, charlie 1
someID, 456
I was heading down the path of using SelectMany() and so forth, but could not wrangle it to do what I am after.
I've been sort of waddling around with things like this:
var obj = data.Values.SelectMany<object, Dictionary<string, object>>(x => x);
But I am not able to satisfy the compiler. Yes, I am lost.
I am using .NET 3.5.
解决方案Func<Dictionary<string, object>, IEnumerable<KeyValuePair<string, object>>> flatten = null;
flatten = dict => dict.SelectMany(kv =>
kv.Value is Dictionary<string,object>
? flatten((Dictionary<string,object>)kv.Value)
: new List<KeyValuePair<string,object>>(){ kv}
);
var flatList = flatten(data).ToList();
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