由网友(翱翔)分享简介：标题表明，我已经一个想法，这是怎么回事，但我无法解释。我试图订购名单，LT;字符串[]＆GT; 动态每个列，先上和最小结束长度所有阵列。The title suggests that i've already an idea what's going on, but i cannot explain it. I've...

标题表明，我已经一个想法，这是怎么回事，但我无法解释。我试图订购名单，LT;字符串[]＆GT; 动态每个列，先上和最小结束长度所有阵列。

The title suggests that i've already an idea what's going on, but i cannot explain it. I've tried to order a List<string[]> dynamically by each "column", beginning with the first and ending with the minimum Length of all arrays.

所以这个样品是在 2 ，因为最后的String [] 只有两个元素：

So in this sample it is 2, because the last string[] has only two elements:

List<string[]> someValues = new List<string[]>();
someValues.Add(new[] { "c", "3", "b" });
someValues.Add(new[] { "a", "1", "d" });
someValues.Add(new[] { "d", "4", "a" });
someValues.Add(new[] { "b", "2" });

现在我已经尝试由第一和第二列订制。我能做到这一点静态地以这种方式：

Now i've tried to order all by the first and second column. I could do it statically in this way:

someValues = someValues
    .OrderBy(t => t[0])
    .ThenBy(t => t[1])
    .ToList();

但是，如果我不知道列的数目我可以用这个循环（这是我的想法）：

But if i don't know the number of "columns" i could use this loop(that's what I thought):

int minDim = someValues.Min(t => t.GetLength(0));  // 2
IOrderedEnumerable<string[]> orderedValues = someValues.OrderBy(t => t[0]);
for (int i = 1; i < minDim; i++)
{
    orderedValues = orderedValues.ThenBy(t => t[i]);
}
someValues = orderedValues.ToList();  // IndexOutOfRangeException 

但是，这并不工作，它无法与 IndexOutOfRangeException 在最后一行。调试器告诉我，我是 2 在那个时候，所以for循环的条件似乎被忽略，我已 == minDim 。

But that doesn't work, it fails with an IndexOutOfRangeException at the last line. The debugger tells me that i is 2 at that time, so the for-loop condition seems to be ignored, i is already == minDim.

为什么会这样呢？什么是正确的途径呢？

Why is that so? What is the correct way for this?

推荐答案

这是同样的问题，因为很多人曾与的foreach 回路pre C＃5

It's the same problem as lots of people had with foreach loops pre C# 5.

orderedValues = orderedValues.ThenBy(t => t[i]);

的我将不会被直到你调用评估 .ToList（）此时它的值是2因为这是的退出条件的循环。

The value of i will not be evaluated until you call .ToList() at which point it is 2 since that's the exit condition of the for loop.

您可以引入一个新的局部变量的for循环的内部来解决它：

You can introduce a new local variable inside the for-loop to fix it:

for (int i = 1; i < minDim; i++)
{
    var tmp = i;
    orderedValues = orderedValues.ThenBy(t => t[tmp]);
}

有关更多信息，你可以看看关于关闭了被认为是有害循环变量。

For more information you could take a look at Eric Lippert's blog post about Closing over the loop variable considered harmful.