由网友(-安于此生丶ˉTaurus)分享简介：我的应用程序接收到短信时，被调用的接收器。我想用一个简单的1按钮对话框通知用户。My application has a receiver which is invoked when an SMS is received. I want to notify the user with a simple 1 butto...

我的应用程序接收到短信时，被调用的接收器。我想用一个简单的1按钮对话框通知用户。

My application has a receiver which is invoked when an SMS is received. I want to notify the user with a simple 1 button dialog box..

这是我的code：

AlertDialog.Builder builder = new AlertDialog.Builder(context);
        builder.setMessage("Hello dude").setCancelable(false).setPositiveButton("Got you", new DialogInterface.OnClickListener() {


            @Override
            public void onClick(DialogInterface dialog, int which) {
                // TODO Auto-generated method stub
                //mp.stop();

            }
        }).show();

但是，它抛出一个异常：

But, it is throwing an exception :

android.view.WindowManager $ BadTokenException

android.view.WindowManager$BadTokenException

请帮忙...

推荐答案

首先，你无法显示一个对话框，一个服务或的BroadcastReceiver 。

First, you cannot display a dialog from a Service or BroadcastReceiver.

二，请不要打断用户。正确的方法让用户知道这样的事情发生的背景是显示一个通知。

Second, please DO NOT INTERRUPT THE USER. The proper way to let the user know about something like this that occurred in the background is to display a Notification.