如何拒绝/关闭特定的来电号码号码

由网友(长发及腰记得蹲坑要撩i)分享简介:在我的应用程序,我想阻止特定的传入number.I做谷歌,并遵循的禁止来电 - 安卓。但是,这code是不工作的我,我正在测试的安卓2.3.5 在这里,我没有任何活动类。 >>第一类是扩展的BroadcastReceiver。 的manifest.xml < XML版本=1.0编码=UTF-8&GT?;&L...

在我的应用程序,我想阻止特定的传入number.I做谷歌,并遵循的禁止来电 - 安卓。但是,这code是不工作的我,我正在测试的安卓2.3.5

在这里,我没有任何活动类。 >>第一类是扩展的BroadcastReceiver。

的manifest.xml

 < XML版本=1.0编码=UTF-8&GT?;
<舱单的xmlns:机器人=htt​​p://schemas.android.com/apk/res/android
包=com.blocknumber
安卓版code =1
机器人:VERSIONNAME =1.0>

<用途-SDK
    安卓的minSdkVersion =8
    机器人:targetSdkVersion =17/>

<使用-权限的Andr​​oid:名称=android.permission.READ_PHONE_STATE/>
<使用-权限的Andr​​oid:名称=android.permission.CALL_PHONE/>
<使用-权限的Andr​​oid:名称=android.permission.MODIFY_PHONE_STATE/>
<使用-权限的Andr​​oid:名称=android.permission.PROCESS_INCOMING_CALLS/>

<应用
    机器人:allowBackup =真
    机器人:图标=@可绘制/ ic_launcher
    机器人:标签=@字符串/ APP_NAME
    机器人:主题=@风格/ AppTheme>
    <接收机器人:名称=。MainActivity>
        <意向滤光器>
            <作用机器人:名称=android.intent.action.PHONE_STATE/>
        &所述; /意图滤光器>
    < /接收器>
< /用途>
 

MainActivity.class

 公共类MainActivity扩展的BroadcastReceiver {

公共无效的onReceive(上下文的背景下,意图意图){
    串blockedNumbers [] = {XXXXXXXXXX,XXXXXXXXXX};
    叠B = intent.getExtras();
    / *
     *字符串incommingNumber = B
     * .getString(TelephonyManager.EXTRA_INCOMING_NUMBER);
     * /
    串incommingNumber = b.getString(incoming_number);
    Log.e(进来的数量========>中,incommingNumber);
    //字符串状态= intent.getStringExtra(TelephonyManager.EXTRA_STATE);

    的for(int i = 0; I< blockedNumbers.length;我++){
        Log.e(进来的>>>>>>>>>>>>> ======>中,+ I);
        如果(incommingNumber.equalsIgnoreCase(blockedNumbers [I])){
            TelephonyManager电话=(TelephonyManager)上下文
                    .getSystemService(Context.TELEPHONY_SERVICE);
            尝试 {
                类<> C =的Class.forName(telephony.getClass()的getName());
                方法米= c.getDeclaredMethod(getITelephony);
                m.setAccessible(真正的);
                ITelephony telephonyService =(ITelephony)M
                        .invoke(电话);
                // telephonyService.silenceRinger();
                telephonyService.endCall();
            }赶上(例外五){
                e.printStackTrace();
            }
        }
    }

}
}
 
手机怎样拒绝全部来电

ITelephony

 公共接口ITelephony {

    布尔结束呼叫();

    无效answerRingingCall();

    //无效silenceRinger();

}
 

解决方案

最后,解决问题, 创建IDL接口获取核心电话服务 包的名称必须是 com.android.internal.telephony

文件名: ITelephony.aidl //首先在这里我createing ITelephony.java

对于创建的 .aidl 文件最新及GT;文件 ITelephony.aidl

和遵循的步骤禁止在Android的呼叫,而无需用户干预的例子。

In my application I want to block the specific incoming number.I do google,and following Blocking Incoming call - Android. But this code is not working for me.I am testing on android 2.3.5

Here I have no activity class. >> First class is extends BroadcastReceiver.

manifest.xml

<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.blocknumber"
android:versionCode="1"
android:versionName="1.0" >

<uses-sdk
    android:minSdkVersion="8"
    android:targetSdkVersion="17" />

<uses-permission android:name="android.permission.READ_PHONE_STATE" />
<uses-permission android:name="android.permission.CALL_PHONE" />  
<uses-permission android:name="android.permission.MODIFY_PHONE_STATE" /> 
<uses-permission android:name="android.permission.PROCESS_INCOMING_CALLS" />

<application
    android:allowBackup="true"
    android:icon="@drawable/ic_launcher"
    android:label="@string/app_name"
    android:theme="@style/AppTheme" >
    <receiver android:name=".MainActivity" >
        <intent-filter>
            <action android:name="android.intent.action.PHONE_STATE" />
        </intent-filter>
    </receiver>
</application>

MainActivity.class

public class MainActivity extends BroadcastReceiver {

public void onReceive(Context context, Intent intent) {
    String blockedNumbers[] = { "xxxxxxxxxx", "xxxxxxxxxx" };
    Bundle b = intent.getExtras();
    /*
     * String incommingNumber = b
     * .getString(TelephonyManager.EXTRA_INCOMING_NUMBER);
     */
    String incommingNumber = b.getString("incoming_number");
    Log.e("Incomming number========>", incommingNumber);
    // String state = intent.getStringExtra(TelephonyManager.EXTRA_STATE);

    for (int i = 0; i < blockedNumbers.length; i++) {
        Log.e("Incomming >>>>>>>>>>>>>========>", "" + i);
        if (incommingNumber.equalsIgnoreCase(blockedNumbers[i])) {
            TelephonyManager telephony = (TelephonyManager) context
                    .getSystemService(Context.TELEPHONY_SERVICE);
            try {
                Class<?> c = Class.forName(telephony.getClass().getName());
                Method m = c.getDeclaredMethod("getITelephony");
                m.setAccessible(true);
                ITelephony telephonyService = (ITelephony) m
                        .invoke(telephony);
                // telephonyService.silenceRinger();
                telephonyService.endCall();
            } catch (Exception e) {
                e.printStackTrace();
            }
        }
    }

}
}

ITelephony

public interface ITelephony {

    boolean endCall();

    void answerRingingCall();

    //void silenceRinger();

}

解决方案

Finally, solve the issue, Create IDL interface for getting core Telephony service package name must be com.android.internal.telephony

FileName : ITelephony.aidl // First Here I am createing ITelephony.java

For the create .aidl file New > File and write ITelephony.aidl

And follow the steps Blocking a call without user intervention in android with an example.

阅读全文

相关推荐

最新文章