好吧,我知道这之前已经(Execute选择使用Ajax或JavaScript ),但答案下拉列表选项后,同一页上的PHP脚本不是为别人谁也从来没有使用AJAX非常有帮助。如何运行像中创建一个查询,如果有人选择从下拉选项?
< HEAD>
&所述;脚本的src =https://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js>&所述; /脚本>
< /头>
< H3>受试对象; / H3>
<选择名称=allbooks>
<期权价值=无>< /选项>
<期权价值=allbooks>所有图书< /选项>
< /选择>
< PHP
$查询=SELECT * FROM书或死亡(错误的磋商。mysqli_error($连接)。);
$书= $连接 - >查询($查询);
?>
解决方案
首先,你必须触发AJAX请求,通过使用Javascript。不过,我会指导您使用jQuery(JavaScript库)。
您的HTML:
<选择名称=allbooksID =allbooks>
<期权价值=无>< /选项>
<期权价值=allbooks>所有图书< /选项>
< /选择>
< DIV ID =秀>
<! - 项目被这里显示 - >
< / DIV>
在此之后,下载 jQuery的。
然后让执行脚本:
<脚本SRC =jQuery的-1.9.1.min.js>< / SCRIPT> < - !CHANGE jQuery的文件根据版本您已经下载 - >
<脚本类型=文/ JavaScript的>
$(文件)。就绪(函数(){/ * prePARE脚本* /
$(#allbooks)。改变(函数(){/ *当您更改,然后从选择字段* /
VAR allbooks = $(本).VAL(); / *获取所选数据的值* /
变种dataString =allbooks =+ allbooks; / *存储到数据串* /
$阿贾克斯({/ *然后Ajax调用* /
类型:POST,/ *类型的方法用来传递数据* /
网址:GET-data.php/ *页,在这里,我们将传递数据* /
数据:dataString,/ *数据,我们将路过* /
成功:函数(结果){/ *获取要返回数据* /
$(#秀)HTML(结果); / *返回的数据将被显示在此DIV * /
}
});
});
});
< / SCRIPT>
然后让创建 GET-data.php
将接收通过AJAX发送的数据。
如果(!空($ _ POST [allbooks])){
/ *做你的查询这里得到你想要的输出* /
回声$输出; / *打印您需要的输出,它会返回到原来的页面* /
}
您可以检查这个例子 - 。的jsfiddle
Okay I know this has been answered before (Execute PHP script on same page after selecting a dropdown list option using Ajax or JavaScript) but the answers weren't very helpful for someone who has never used AJAX before. How do I run a query like the one created if someone selects an option from the drop down?
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js"></script>
</head>
<h3>Subject</h3>
<select name="allbooks" >
<option value="none" ></option>
<option value="allbooks" >All Books</option>
</select>
<?php
$query = "SELECT * FROM books" or die("Error in the consult.." . mysqli_error($connection));
$books = $connection->query($query);
?>
解决方案
First is, you have to trigger the AJAX request by using Javascript. But I'll be guiding you by using jQuery (a Javascript library).
Your HTML:
<select name="allbooks" id="allbooks">
<option value="none" ></option>
<option value="allbooks" >All Books</option>
</select>
<div id="show">
<!-- ITEMS TO BE DISPLAYED HERE -->
</div>
After that, download jQuery.
Then lets do the script:
<script src="jquery-1.9.1.min.js"></script> <!-- CHANGE THE JQUERY FILE DEPENDING ON THE VERSION YOU HAVE DOWNLOADED -->
<script type="text/javascript">
$(document).ready(function(){ /* PREPARE THE SCRIPT */
$("#allbooks").change(function(){ /* WHEN YOU CHANGE AND SELECT FROM THE SELECT FIELD */
var allbooks = $(this).val(); /* GET THE VALUE OF THE SELECTED DATA */
var dataString = "allbooks="+allbooks; /* STORE THAT TO A DATA STRING */
$.ajax({ /* THEN THE AJAX CALL */
type: "POST", /* TYPE OF METHOD TO USE TO PASS THE DATA */
url: "get-data.php", /* PAGE WHERE WE WILL PASS THE DATA */
data: dataString, /* THE DATA WE WILL BE PASSING */
success: function(result){ /* GET THE TO BE RETURNED DATA */
$("#show").html(result); /* THE RETURNED DATA WILL BE SHOWN IN THIS DIV */
}
});
});
});
</script>
Then lets create the get-data.php
which will receive the data sent through AJAX.
if(!empty($_POST["allbooks"])){
/* DO YOUR QUERY HERE AND GET THE OUTPUT YOU WANT */
echo $output; /* PRINT THE OUTPUT YOU WANT, IT WILL BE RETURNED TO THE ORIGINAL PAGE */
}
You can check this example - JSfiddle.
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