由网友(別扯、扯多了都是事故)分享简介：例如code：$.ajax({url: someUrl,data: someData,dataType: "json",type: "POST",contentType: "application/json; charset=utf-8",success: function () { },});...

例如code：

        $.ajax({
                url: someUrl,
                data: someData,
                dataType: "json",
                type: "POST",
                contentType: "application/json; charset=utf-8",
                success: function () { },
        });                

        window.location = urlToGoTo;

可以说，上述code运行时，用户点击一个按钮。

Lets say the above code runs when the user clicks a button.

由于Ajax调用是异步的，什么都会code等以上运行时发生的呢？使用像小提琴手的工具，它看起来像有时AJAX调用成功，有时它永远不会被调用（Ajax调用得到机会运行前，即当前网页被更​​改）。

Since the ajax call is asynchronous, what will happen when code such the above runs ? Using a tool like Fiddler, it looks like sometimes the ajax call succeeds, and sometimes it never gets called (i.e. the current web page is changed before the ajax call gets a chance to run).

在这样的情况下，你应该总是等待AJAX​​调用设置window.location（例如，在阿贾克斯完整的事件）之前完成？

In cases like this, should you always wait for the ajax call to complete before setting window.location (e.g. in the ajax "complete" event) ?

只是想获得一些洞察到发生了什么引擎盖下。

Just trying to get some insight into what is happening under the hood.

推荐答案

您可以做重定向的成功回调

You can do the redirect in the success callback

$.ajax({
    url: someUrl,
    data: someData,
    dataType: "json",
    type: "POST",
    contentType: "application/json; charset=utf-8",
    success: function () {
        window.location = urlToGoTo;
    }
});

如何返回一个异步调用的响应