由网友(巴拉拉能量作业消失)分享简介：能否请你帮我如何结合下面的结果1和结果2 JSON对象为单JSON这样的，我有名字，没有，平均，Subject1，Subject2成单一的JSON对象。我使用它jQuery的AJAX。Could you please help me on how to combine the below Result1 and Re...

能否请你帮我如何结合下面的结果1和结果2 JSON对象为单JSON这样的，我有名字，没有，平均，Subject1，Subject2成单一的JSON对象。我使用它jQuery的AJAX。

Could you please help me on how to combine the below Result1 and Result2 JSON objects into single JSON such that i have Name,No,Avg,Subject1,Subject2 into single JSON object. I am using it in JQUERY AJAX.

{"Result1":"[{"NAME" : "Mark","No" : "23544","Avg" : "49"}]"}

{"Result2":"[{"Subject1" : "Maths","Subject2" : "Computers"}]"}

请帮忙。

感谢

推荐答案

请参阅 jQuery.extend（）

var x = {"Result1":"[{"NAME" : "Mark","No" : "23544","Avg" : "49"}]"}
var y = {"Result2":"[{"Subject1" : "Maths","Subject2" : "Computers"}]"}

var z = jQuery.extend({}, x.Result1[0], y.Result2[0]);
// z.NAME, z.No, z.Avg, z.subject1...

我不知道你是否已经解析JSON字符串转换为JavaScript对象之中;但见 jQuery.parseJSON（） 就看你如何做到这一点（请注意， parseJSON（）会，如果你传递无效的JSON引发错误）。

I'm not sure whether you've parsed the JSON string into a JavaScript object yet; but see jQuery.parseJSON() to see how you do this (be aware; parseJSON() will throw an error if you pass it invalid JSON).