通过看这个图片我想你会明白我的问题pretty的还有:
By looking at this image I think you will understand my problem pretty well:
(图像中删除 - 网址不再有效,返回现在的广告)的
所以基本上我想要一个函数,根据我多少对象前添加需要一个对象作为参数,并给出了此对象的正确坐标。
So basically I want a function that takes an object as parameter and gives this object the correct coordinates based on how many objects I've added before.
比方说,我想补充所有这些对象的数组:
Let's say I would add all these objects to an array:
objectArray[]
我每次添加一个新的对象: objectArray.add(对象)
Each time I add a new object: objectArray.add(object)
在 object.x
和 object.y
坐标将根据某种算法进行设置:
The object.x
and object.y
coordinates will be set based on some algorithm:
object.x = ?
object.y = ?
(我用Java开发的)
(I'm working in Java)
感谢您的帮助。
推荐答案
下面是一个不依赖于一个循环的封闭形式的解决方案...我不顺手的Java,因此它在C#中,但它使用基本操作。
Here's the closed-form solution that doesn't rely on a loop... I'm not handy with Java, so it's in C#, but it uses basic operations.
static void SpiralCalc(int i) {
i -= 2;
// Origin coordinates
int x = 100, y = 100;
if (i >= 0) {
int v = Convert.ToInt32(Math.Truncate(Math.Sqrt(i + .25) - .5));
int spiralBaseIndex = v * (v + 1);
int flipFlop = ((v & 1) << 1) - 1;
int offset = flipFlop * ((v + 1) >> 1);
x += offset; y += offset;
int cornerIndex = spiralBaseIndex + (v + 1);
if (i < cornerIndex) {
x -= flipFlop * (i - spiralBaseIndex + 1);
} else {
x -= flipFlop * (v + 1);
y -= flipFlop * (i - cornerIndex + 1);
}
}
// x and y are now populated with coordinates
Console.WriteLine(i + 2 + "t" + x + "t" + y);
}
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