由网友(执笔画倾城)分享简介：我想通过以下code片段做在角的JS通配符（*）路由：I am trying to do a wildcard (*) routing in Angular js through following code snippet:$routeProvider.when('/something/:action/:id/:...

我想通过以下code片段做在角的JS通配符（*）路由：

I am trying to do a wildcard (*) routing in Angular js through following code snippet:

$routeProvider.when('/something/:action/:id/:params*/', {

  templateUrl : "/js/angular/views/sample/index.html",

  controller : 'SampleCtrl'

}).otherwise({

  redirectTo: '/something/all' //This exists in real code

});

样本路径：/＃/事/信息/ 201/1

在调用这个网址就执行，否则方法。我在做什么错在这里？在此先感谢

On calling this url it executes the otherwise method. What am I doing wrong here? Thanks in advance

推荐答案

的 $ routeProvider 不支持标准的正则表达式，但它支持的命名组：

The $routeProvider does not support standard regexp but it does support named groups:

  

路径可以包含开始用冒号命名组（：名称）。所有字符，直到达到下一个斜线都以给定名字匹配，并存储在$ routeParams当路线匹配

path can contain named groups starting with a colon (:name). All characters up to the next slash are matched and stored in $routeParams under the given name when the route matches.

路径可以包含开头的星号（*名）命名组。所有字符都急切地存储在$ routeParams以给定名字的时候路由匹配。

path can contain named groups starting with a star (*name). All characters are eagerly stored in $routeParams under the given name when the route matches.

所以，你应该尝试

$ routeProvider.when（'/事/：动作/：ID /：PARAMS / *休息'

将匹配 /＃/事/信息/ 201/1 /不管/你/说