由网友(海是倒过来的天)分享简介：在我的应用程序中，我有一个玩家和许多敌人(大约 100 多个)..我不想使用 CGRects，因为它不适合敌人.有没有例子如何在 cocos2d 中使用许多精灵进行像素完美碰撞检测?in my app I have a player and many enemies (about 100+)..I don't wan...

在我的应用程序中，我有一个玩家和许多敌人(大约 100 多个)..我不想使用 CGRects，因为它不适合敌人.有没有例子如何在 cocos2d 中使用许多精灵进行像素完美碰撞检测?

in my app I have a player and many enemies (about 100+)..I don't want to use CGRects because it doesn't fits to the enemies. Is there any example how to do pixel perfect collision detection in cocos2d with many sprites?

一些解释会很棒;)

非常感谢！

编辑:我正在使用 CCSprite 和 .png 文件.png 具有透明度，但它应该只检测非透明像素上的碰撞.

EDIT: I'm using CCSprite and .png files. the png has transparency but it should only detect a collision on non-transparency pixels.

我的敌人是圆形的.

推荐答案

圆-圆碰撞最简单..计算最快..希望你知道玩家的半径和敌人的半径..让20是玩家的半径和 10 是敌人的半径.. 一个简单的计算是:

Circle-circle collision is the easiest.. And computing is the fastest.. I hope you know the radius of the player and radius of enemy.. Let 20 be radius of player and 10 be radius of enemy.. A simple calculation would be:

float dx = player.spr.x - enemy.spr.x;
float dy = player.spr.y - enemy.spr.y;
float dxy = dx*dx + dy*dy;
float collisionRad = (20+10)*(20+10);

if(dxy<= collisionRad)
{
//collision
}

我们正在使用勾股定理计算 2 点之间的距离.http://en.wikipedia.org/wiki/Pythagorean_theorem

We are calculating distance between 2 points using the Pythagorean Theorem.. http://en.wikipedia.org/wiki/Pythagorean_theorem