由网友(别拿牙签当大炮)分享简介：我此刻有些无奈。我有以下code public class ListViewAdapter extends ArrayAdapter {private final Context context;private final int textViewResourceId;priv...

我此刻有些无奈。

我有以下code

public class ListViewAdapter<String> extends ArrayAdapter<String> {
private final Context context;
private final int textViewResourceId;
private final int[] itemResourceIds;
private final ArrayList<String> list;

public ListViewAdapter(Context context, int textViewResourceId,
    int[] itemResourceIds, ArrayList<String> list) {
        super(context, textViewResourceId, itemResourceIds, list);
        this.context = context;
        this.textViewResourceId = textViewResourceId;
        this.itemResourceIds = itemResourceIds;
        this.list = list;
    }

@Override
public View getView(int position, View convertView, ViewGroup parent) {
    // some code...
}
}

但是Eclipse标志着超（...）行，我想不通为什么。

But eclipse marks the super(...) line, and I can't figure out why.

它告诉我：

The constructor ArrayAdapter<String>(Context, int, int[], ArrayList<String>) is undefined

但我没有这样准确界定呢？

But didn't I define it exactly this way?

请帮我在这里。

推荐答案

当您使用超强，你必须调用父类的构造函数中定义的一个

when you use super, you have to call one of the parent class defined constructors

ArrayAdapter，你可以看到这里，有这样可用的构造函数：

ArrayAdapter, as you can see here, has this available constructors:

ArrayAdapter(Context context, int resource)

ArrayAdapter(Context context, int resource, int textViewResourceId)

ArrayAdapter(Context context, int resource, String[] objects)

ArrayAdapter(Context context, int resource, int textViewResourceId, String[] objects)

ArrayAdapter(Context context, int resource, List<String> objects)

ArrayAdapter(Context context, int resource, int textViewResourceId, List<T> objects)

所以，你必须给他们打电话之一

So you have to call one of them

和你调用

超（背景下，textViewResourceId，itemResourceIds，清单）;那是  ArrayAdapter（上下文，INT，INT []，ArrayList中），而且不存在。

super(context, textViewResourceId, itemResourceIds, list); that is ArrayAdapter(Context, int, int[], ArrayList) and does not exists.

，而不是一个int数组， itemResourceIds 应该是一个int。

instead of an array of int, itemResourceIds should be an int.

如何解决它取决于什么是itemResources的内容[];

How to fix it depends on what are the contents of itemResources[];

认为这样的：

ArrayAdapter(Context context, int resource,  int textViewResourceId, List<String> objects)

接收XML布局文件的ID，然后文本字段的ID。

receives the id of an xml layout file, and then the id of a text field.

这

ArrayAdapter(Context context, int resource, List<T> objects)

接收XML文件的仅仅是ID

receives just the id of the xml file

也许你可能想只是叫

 super(context, itemResourceIds[0],textViewResourceId,  list); 

或只是

 super(context, itemResourceIds[0], list); 

但要看是什么 itemResourceIds 的内容居然都是。

如果您正在实现整个适配器，你不是真的关心你传递给家长什么ID，所以你可以简单地将其更改为

If you are implementing the whole adapter, you dont really care about what id you are passing to the parent, so you can simply change it to

 super(context, 0, list); 

由于在父类没有人goint使用它。

since in the parent class nobody is goint to use it.

不管怎么说，如果你是goint自己来实现的一切，你可以考虑延长 BaseAdapter 而不是 ArrayAdaper 自BaseAdapter犯规需要在构造函数中的任何参数，而且很可能你不需要一个ArrayAdapter的任何功能。

Anyways, if you are goint to implement everything by yourself, you can consider extending BaseAdapter instead of ArrayAdaper since BaseAdapter doesnt need any parameter in the constructor, and probably you dont need any functionality of the ArrayAdapter.