由网友(猫旅人)分享简介：由于系统（如网站），允许用户自定义背景色为某些部分，但不是字体颜色（保留的选项，以最小数），有没有办法以编程方式确定一个光或黑字体颜色是必要的吗？Given a system (a website for instance) that lets a user customize the background colo...

由于系统（如网站），允许用户自定义背景色为某些部分，但不是字体颜色（保留的选项，以最小数），有没有办法以编程方式确定一个光或黑字体颜色是必要的吗？

Given a system (a website for instance) that lets a user customize the background color for some section but not the font color (to keep number of options to a minimum), is there a way to programmatically determine if a "light" or "dark" font color is necessary?

我敢肯定，有一些算法，但我不知道足够的颜色，亮度等，以数字出来我自己。

I'm sure there is some algorithm, but I don't know enough about colors, luminosity, etc to figure it out on my own.

推荐答案

我遇到过类似的问题。我必须找到在选择对比字体颜色，显示在colorscales /热图文本标签的好方法。它必须是通用的方法和产生的颜色必须是好看，这意味着简单的发电互补色不是很好的解决方案 - 有时它产生的怪，非常密集的颜色是很难看和读

I encountered similar problem. I had to find a good method of selecting contrastive font color to display text labels on colorscales/heatmaps. It had to be universal method and generated color had to be "good looking", which means that simple generating complementary color was not good solution - sometimes it generated strange, very intensive colors that were hard to watch and read.

长时间的测试，并试图解决这个问题之后，我发现最好的办法是选择白色​​字体的黑暗的颜色，黑色字体为光明的色彩。

After long hours of testing and trying to solve this problem, I found out that the best solution is to select white font for "dark" colors, and black font for "bright" colors.

下面是函数的例子我正在使用C＃：

Here's an example of function I am using in C#:

Color ContrastColor(Color color)
{
    int d = 0;

    // Counting the perceptive luminance - human eye favors green color... 
    double a = 1 - ( 0.299 * color.R + 0.587 * color.G + 0.114 * color.B)/255;

    if (a < 0.5)
       d = 0; // bright colors - black font
    else
       d = 255; // dark colors - white font

    return  Color.FromArgb(d, d, d);
}

这是测试了许多不同的colorscales（彩虹，灰度，热，冰，和许多其他），并是唯一的万能的方法，我发现了。

This was tested for many various colorscales (rainbow, grayscale, heat, ice, and many others) and is the only "universal" method I found out.

修改 改变计算公式 A 来感知亮度 - 它确实看起来更好！已经实现了它在我的软件，看上去很不错。

Edit Changed the formula of counting a to "perceptive luminance" - it really looks better! Already implemented it in my software, looks great.

编辑2 @WebSeed提供该算法的一个伟大的工作示例： HTTP：//$c$cpen.io/WebSeed/full/ pvgqEq /

Edit 2 @WebSeed provided a great working example of this algorithm: http://codepen.io/WebSeed/full/pvgqEq/