由网友(你在远离我)分享简介：我看过这个网站，这是需要自定义ListView的setOnItemSelectedListener和setOnItemClickListener如果我们想知道的SelectedItem的指数（.getSelectedItemPosition（））。所以这是我做的，但它确实在SekectedItem的不是卖场的位置，而不...

我看过这个网站，这是需要自定义ListView的setOnItemSelectedListener和setOnItemClickListener如果我们想知道的SelectedItem的指数（.getSelectedItemPosition（））。所以这是我做的，但它确实在SekectedItem的不是卖场的位置，而不是我一直-1 ...

I have read on this site that it is necessary to customize the setOnItemSelectedListener and setOnItemClickListener of a ListView if we want to know the Index of the SelectedItem (.getSelectedItemPosition()). So that is what I do but it does not stores the position of the SekectedItem, instead i have always -1...

我想要做的就是给用户的方式选定和项目，并点击一个按钮来删除列表中的项目。

What I want to do is just to give the user a way to delete items from a list by selected and Item and Clicking a button.

见$ C $低于C：

    listViewPeople.setOnItemClickListener(new ListView.OnItemClickListener() {
        @Override
        public void onItemClick(AdapterView<?> a, View v, int i, long l) {
            try {
                // Remembers the selected Index
                listViewPeopleId = listViewPeople.getSelectedItemPosition();
            }
            catch(Exception e) {
                System.out.println("Nay, cannot get the selected index");
            }
        }
    });

    listViewPeople.setOnItemSelectedListener(new ListView.OnItemSelectedListener() {
        @Override
        public void onItemSelected(AdapterView<?> a, View v, int i, long l) {
            try {
                // Remembers the selected Index
                listViewPeopleId = listViewPeople.getSelectedItemPosition();
                System.out.println("Yay, set the selected index " + listViewPeopleId);
            }
            catch(Exception e) {
                System.out.println("Nay, cannot get the selected index " + listViewPeopleId);
            }
        }

        @Override
        public void onNothingSelected(AdapterView<?> arg0) {
            try {
                // Remembers nothing selected
                listViewPeopleId = -1;
                System.out.println("Yay, set that nothing is selected " + listViewPeopleId);
            }
            catch(Exception e) {
                System.out.println("Nay, cannot set that nothing is selected " + listViewPeopleId);
            }
        }
    });

什么是错？

感谢您的帮助！

克里斯托夫

推荐答案

而不是做的 listViewPeople.getSelectedItemPosition（）; 尝试使用INT I参数来获得索引。

Instead of doing listViewPeople.getSelectedItemPosition(); try using the int i parameter to get the index.