由网友(杀死喜欢)分享简介：我是新的Python和我想的写 recAdd 在我递归斐波纳契版本的最终值。这是我的code：I'm new in Python and I'm trying the write to final value of recAdd on my fibonacci recursive version. Here is...

我是新的Python和我想的写 recAdd 在我递归斐波纳契版本的最终值。这是我的code：

I'm new in Python and I'm trying the write to final value of recAdd on my fibonacci recursive version. Here is my code:

recAdd=0
def fibonacciRecursive(n):
    global recAdd
    if n==1 or n==0:        
        return n
    else:
        recAdd=recAdd+1
        return fibonacciRecursive(n-1)+fibonacciRecursive(n-2)
    print(recAdd)

在我打电话给我的功能，它只返回斐波那契数值，而不是 recAdd 。我要同时打印它们。我应该怎么做才能打印 recAdd 值？

After I called my function, it returns only fibonacci value and not recAdd.I want to print both of them. What should I do to print the recAdd value?

推荐答案

您需要迪登的打印，并将其放置在调用函数之后

You need to dedent the print and place it after you call the function

def fibonacciRecursive(n):
    global recAdd
    if n == 1 or n == 0:        
        return n  # <-- should this be return 1?
    else:
        recAdd = recAdd + 1
        return fibonacciRecursive(n - 1) + fibonacciRecursive(n - 2)

recAdd = 0
fibonacciRecursive(5)
print(recAdd)

您可以在一个包装封装本

You could encapsulate this in a wrapper

def fib_aux(n):
    global recAdd
    recAdd = 0
    fibonacciRecursive(5)
    print(recAdd)

然后，只需拨打

Then just call

fib_aux(5)

埋葬在功能逻辑是尴尬。这里有一种方法

Burying the logic in the function is awkward. Here is one way

def fibonacciRecursive(n, print_recAdd=True):
    global recAdd
    if n == 1 or n == 0:        
        retval = n  # <-- should this be 1?
    else:
        recAdd = recAdd + 1
        retval = fibonacciRecursive(n - 1, False) + fibonacciRecursive(n - 2, False)
    if print_recAdd:
        print recAdd
    return retval