由网友(续写____旧情缘)分享简介：我如何创建一个JSON这个格式的Andr​​oid版本：从那时起，我将通过将解析JsonArray那么对象的API。还是会好起来的，如果只是为了传递一个JSON对象？因为我只需要插入每个服务呼叫的1交易。How can I create a JSON with this format in Android:Si...

我如何创建一个JSON这个格式的Andr​​oid版本： 从那时起，我将通过将解析JsonArray那么对象的API。 还是会好起来的，如果只是为了传递一个JSON对象？因为我只需要插入每个服务呼叫的1交易。

How can I create a JSON with this format in Android: Since the API that I will be passing will parse JsonArray then the object. Or would it be okay if just to pass a json object? Since I will just have to insert 1 transaction per service call.

    {
        "student": [

            {
                "id": 1,
                "name": "John Doe",
                "year": "1st",
                "curriculum": "Arts",
                "birthday": 3/3/1995

            },
            {
                "id": 2,
                "name": "Michael West",
                "year": "2nd",
                "curriculum": "Economic",
                "birthday": 4/4/1994
            }
        ]
    }

我所知道的只是的JSONObject。 赞一个。

What I know is only the JSONObject. Like this one.

     JSONObject obj = new JSONObject();
            try {
                obj.put("id", "3");
                obj.put("name", "NAME OF STUDENT");
                obj.put("year", "3rd");
                obj.put("curriculum", "Arts");
                obj.put("birthday", "5/5/1993");

            } catch (JSONException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }

任何想法。谢谢

Any ideas. Thanks

推荐答案

使用下面的code：

JSONObject student1 = new JSONObject();
try {
    student1.put("id", "3");
    student1.put("name", "NAME OF STUDENT");
    student1.put("year", "3rd");
    student1.put("curriculum", "Arts");
    student1.put("birthday", "5/5/1993");

} catch (JSONException e) {
    // TODO Auto-generated catch block
    e.printStackTrace();
}

JSONObject student2 = new JSONObject();
try {
    student2.put("id", "2");
    student2.put("name", "NAME OF STUDENT2");
    student2.put("year", "4rd");
    student2.put("curriculum", "scicence");
    student2.put("birthday", "5/5/1993");

} catch (JSONException e) {
    // TODO Auto-generated catch block
    e.printStackTrace();
}


JSONArray jsonArray = new JSONArray();

jsonArray.put(student1);
jsonArray.put(student2);

JSONObject studentsObj = new JSONObject();
    studentsObj.put("Students", jsonArray);



String jsonStr = studentsObj.toString();

    System.out.println("jsonString: "+jsonStr);